[Solved]-Python Scores Scores 25 56 79 94 99 Ve Already Found Average Average Totalscores Len Score Q37183250

PYTHON

These are the scores

scores = [25, 56, 79, 94, 99]

I’ve already found the average

average = total_scores/len(scores)
print(“Sum of all scores: ” + str(total_scores))
print(“Average: ” + str(average))

How do I make exceptions for those above the average

# use filter() to figure scores that are above average pleasehelp me write a code for inside the paranthesis

above_avg = filter()

Expert Answer

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Answer to PYTHON These are the scores scores = [25, 56, 79, 94, 99] I’ve already found the average average = total_scores/len(scor… . . .