[Solved] Output Following Program Zu Format Specifier Printf Statement Displays Result Sizeof Decim Q37171086

What is the output of the following program, where the zu format specifier in the printf statement below displays the result of sizeof as a decimal integer? #include <stdio.h> #include <string.h> typedef union ( doubled char c[20]; int main() U temp temp.d 11.5; strcpy (temp.c, “CS 354”); printf(“%zu, %f, %sn” , sizeof(temp), return 0; temp . c); temp . d, Runtime error O 28, 11.5, CS 354 O 20, 11.5, CS 354 28, Garbage value, CS 354 20, Garbage value, CS 354 Show transcribed image text What is the output of the following program, where the zu format specifier in the printf statement below displays the result of sizeof as a decimal integer? #include #include typedef union ( doubled char c[20]; int main() U temp temp.d 11.5; strcpy (temp.c, “CS 354”); printf(“%zu, %f, %sn” , sizeof(temp), return 0; temp . c); temp . d, Runtime error O 28, 11.5, CS 354 O 20, 11.5, CS 354 28, Garbage value, CS 354 20, Garbage value, CS 354

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Answer to What is the output of the following program, where the zu format specifier in the printf statement below displays the re… . . .