[Solved] 2a A015 M Long Polymer Rod 0010 Diameter Load 150 N One Day Modeling Rod Standard Linear S Q37289971

ignore the part about plotting with matlab
2a. A0.15 m long polymer rod of 0.010 diameter has load of 150 N on it for one day. Modeling this rod as a standard linear solid, find the axial strain versus time. Give the governing equation and plot the results for the one day of loading using Matlab. Use: k 1.5×105 N/m, k2 3×10 N/m and b 5 GN-s (ie, 5×109) b. For the previous problem, assuming that the load has been in place one day, find the length of the rod at the end of a second day if the load is released at the end of the first day. c. For the rod in the previous two problems, assume that the rod is shortened by 1.5mm and the shortened length is held for one day. What is the stress at the end of one day? Show transcribed image text 2a. A0.15 m long polymer rod of 0.010 diameter has load of 150 N on it for one day. Modeling this rod as a standard linear solid, find the axial strain versus time. Give the governing equation and plot the results for the one day of loading using Matlab. Use: k 1.5×105 N/m, k2 3×10 N/m and b 5 GN-s (ie, 5×109) b. For the previous problem, assuming that the load has been in place one day, find the length of the rod at the end of a second day if the load is released at the end of the first day. c. For the rod in the previous two problems, assume that the rod is shortened by 1.5mm and the shortened length is held for one day. What is the stress at the end of one day?

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Answer to 2a. A0.15 m long polymer rod of 0.010 diameter has load of 150 N on it for one day. Modeling this rod as a standard line… . . .