[solved] – Question 99442

Write an expression that will cause the following code to print “Equal” if the value of sensorReading is “close enough” to targetValue. Otherwise, print “Not equal”. Ex: If targetValue is 0.3333 and sensorReading is (1.0/3.0), output is:
Equal
#include <iostream>
#include <cmath>
using namespace std;

int main() {
double targetValue;
double sensorReading;

cin >> targetValue;
cin >> sensorReading;

if (/* Your solution goes here */) {
cout << “Equal” << endl;
}
else {
cout << “Not equal” << endl;
}

return 0;
}

Expert Answer

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