[solved]-Pri Webster Chemical Company Produces Mastics Caulking Construction Industry Producr Blend Q39670191

Pri Webster Chemical Company produces mastics and caulking for the construction industry. The producr is blended in large mixers and then pumped into tubes and capped. Management is concerned about whether the filling process for tubes of caulking is in statistical control. The process should be centered on 8 ounces per tube. Several samples of eight tubes were taken, each tube was weighed, and the weights in the table below were obtained. 3. Click the icon to view the ounces of caulking per tube data. Click the icon to view the table of factors for calculating three-sigma limits for the x-chart and R-chart a. Assume that only six samples are sufficient and develop the control charts for the mean and the range. Set up the R-chart by specifying the center line and three-sigma control limits below. (Enter your responses rounded to three decimal places.) R-chart UCLR R LCLR Set up the x-chart by specifying the center line and three-sigma control limits below. (Enter your responses rounded to three decimal places.) x-chart UCL LCL our Choose the correct R-chart below. Print O A. O B. O C. O D. 1 UCLR 0.8 0.8 UCLR0.8- UCLRO g 0.6 R 70.44 LOLR 0.8- 0.6 0.6- g06 0.4- 0.4 LCLR 0.2- 0.2 0.2 LCLR 02 LC 0- 2 0- 2 0 2 Sample number 0- 4 6 8 10 Sample number 0 4 10 6 4 8 10 6 Sample number Sample number Choose the correct x-chart below. O B. OA. OC. O D. 5 UCL S 8.3 8.5- UCL UC UCL8.3 81- 8.3 8.3- WA 8.1 8.1 8.1- 7.9 9- LCL 7.7- LCL 7.7 7.7 7.7- 7.5 0 7.5 7.5- 0 7.5 TX 10 8 1 2 4 Sample number 8 10 6 4 6 8 10 Sample number 2 0 4 6 0 2 2 4 8 Sample number Sample number Comment on the results Range Average BangeO Cabeay Comment on the results. Print The process variability is (1) statistical control and the process average is (2) control. statistical control. Thus, the whole process is considered to be (3) Note the decreasing trend in the range, which can be caused by something (4) place. Management should look for assignable causes for the performance in the variability of the process taking in order to (5)- them. 3: More Info Tube number Sample 1 2 3 4 5 6 7: 1 8.28 8.34 8.02 7.94 8.44 8.08 7.81 8.11 7.89 2 7.77 7.86 8.04 8.00 7.89 7.93 8.09 3 8.24 8.18 7.83 7.92 7.90 8.16 7.97 8.07 4 7.87 7.92 8.13 7.99 8.04 781 8.14 7.88 5 8.33 8.22 8.08 8.51 8.41 8.16 8.28 8.09 6 8.13 8.11 8.13 8.14 7.94 8.13 8.14 8.14 4: More Info ur Factors for calculating three-sigma limits for the x-chart and R-chart. 4 7.81 8.13 .92 99 8.04 81 8.14 7.88 8.33 8.22 8.08 8.41 8.28 8.09 8.51 8.16 6 8.13 8.14 8.11 8.13 8.14 7.94 8.13 8.14 4: More Info Factors for calculating three-sigma limits for the x-chart and R-chart Size of Sample Factor for UCL and LCL (n) Factor for LCL for Factor for UCL for for x-chart (A2) R-Chart (D3) R-Chart (D) 1.880 2 0 3.267 1.023 3 0 2.575 2.282 0.729 4 0 0.577 2.115 2.004 0 0.483 1.924 0.076 0.419 1.864 0.136 0.373 1.816 0.184 0.337 1.777 0.223 0.308 (5) O avoid exploit (4) O bad O good (3) O out of O in (2) O out of O in (1) O in O out of LO 5678 9 1 Show transcribed image text Pri Webster Chemical Company produces mastics and caulking for the construction industry. The producr is blended in large mixers and then pumped into tubes and capped. Management is concerned about whether the filling process for tubes of caulking is in statistical control. The process should be centered on 8 ounces per tube. Several samples of eight tubes were taken, each tube was weighed, and the weights in the table below were obtained. 3. Click the icon to view the ounces of caulking per tube data. Click the icon to view the table of factors for calculating three-sigma limits for the x-chart and R-chart a. Assume that only six samples are sufficient and develop the control charts for the mean and the range. Set up the R-chart by specifying the center line and three-sigma control limits below. (Enter your responses rounded to three decimal places.) R-chart UCLR R LCLR Set up the x-chart by specifying the center line and three-sigma control limits below. (Enter your responses rounded to three decimal places.) x-chart UCL LCL our
Choose the correct R-chart below. Print O A. O B. O C. O D. 1 UCLR 0.8 0.8 UCLR0.8- UCLRO g 0.6 R 70.44 LOLR 0.8- 0.6 0.6- g06 0.4- 0.4 LCLR 0.2- 0.2 0.2 LCLR 02 LC 0- 2 0- 2 0 2 Sample number 0- 4 6 8 10 Sample number 0 4 10 6 4 8 10 6 Sample number Sample number Choose the correct x-chart below. O B. OA. OC. O D. 5 UCL S 8.3 8.5- UCL UC UCL8.3 81- 8.3 8.3- WA 8.1 8.1 8.1- 7.9 9- LCL 7.7- LCL 7.7 7.7 7.7- 7.5 0 7.5 7.5- 0 7.5 TX 10 8 1 2 4 Sample number 8 10 6 4 6 8 10 Sample number 2 0 4 6 0 2 2 4 8 Sample number Sample number Comment on the results Range Average BangeO Cabeay
Comment on the results. Print The process variability is (1) statistical control and the process average is (2) control. statistical control. Thus, the whole process is considered to be (3) Note the decreasing trend in the range, which can be caused by something (4) place. Management should look for assignable causes for the performance in the variability of the process taking in order to (5)- them. 3: More Info Tube number Sample 1 2 3 4 5 6 7: 1 8.28 8.34 8.02 7.94 8.44 8.08 7.81 8.11 7.89 2 7.77 7.86 8.04 8.00 7.89 7.93 8.09 3 8.24 8.18 7.83 7.92 7.90 8.16 7.97 8.07 4 7.87 7.92 8.13 7.99 8.04 781 8.14 7.88 5 8.33 8.22 8.08 8.51 8.41 8.16 8.28 8.09 6 8.13 8.11 8.13 8.14 7.94 8.13 8.14 8.14 4: More Info ur Factors for calculating three-sigma limits for the x-chart and R-chart.
4 7.81 8.13 .92 99 8.04 81 8.14 7.88 8.33 8.22 8.08 8.41 8.28 8.09 8.51 8.16 6 8.13 8.14 8.11 8.13 8.14 7.94 8.13 8.14 4: More Info Factors for calculating three-sigma limits for the x-chart and R-chart Size of Sample Factor for UCL and LCL (n) Factor for LCL for Factor for UCL for for x-chart (A2) R-Chart (D3) R-Chart (D) 1.880 2 0 3.267 1.023 3 0 2.575 2.282 0.729 4 0 0.577 2.115 2.004 0 0.483 1.924 0.076 0.419 1.864 0.136 0.373 1.816 0.184 0.337 1.777 0.223 0.308 (5) O avoid exploit (4) O bad O good (3) O out of O in (2) O out of O in (1) O in O out of LO 5678 9 1