[solved]-Using The Data In Appendix C In The Textbook And Given The Pressures Listed Calculate Kpkp And Gg For Each Of The Following Reactions At 298 Kk Part A N2g3h2g2nh3gn2g3h2g2nh3g Express Your A 97934

Using the data in Appendix C in the textbook and giventhe pressures listed,calculate KpKp and ΔGΔG for each of thefollowing reactions at 298 KK.Part A: N2(g)+3H2(g)→2NH3(g)N2(g)+3H2(g)→2NH3(g) Express your answer using two significant figures. Ifyour answer is greater than 10^100 express it in terms ofthe base of the natural logarithm using two decimal places: forexample, exp(200.00)Answer: Kp=6.9×10^5Part B:N2(g)+3H2(g)→2NH3(g)N2(g)+3H2(g)→2NH3(g)Pn2=4.2atm Ph2=7.0atm PNH3= 2.0atmExpress your answer using three significant figures.ΔG=____________kJPart C:2N2H4(g)+2NO2(g)→3N2(g)+4H2O(g)Express your answer using two significant figures. If youranswer is greater than 10^100, express it in terms of the base10 logarithm using two decimal places: for example, 10^(200.00)Kp=_____________Part D:2N2H4(g)+2NO2(g)→3N2(g)+4H2O(g)PN2H4=PNO2=4.5×10^-2atm PN2= 1.9 atm Ph20= 0.7atmExpress your answer using three significant figures.ΔG=_____________kJPart E:N2H4(g)→N2(g)+2H2(g)Express your answer using two significant figures. If youranswer is greater than 10^100 express it in terms of the baseof the natural logarithm using two decimal places: forexample, exp(200.00).Kp=______________PArt FN2H4(g)→N2(g)+2H2(g)PN2H4=0.1atm PN2= 5.1atm PH2= 7.2atmExpress your answer using four significant figures.ΔG=_____________________kJ

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